在php中使用sqlsrv_query从数据库中获取表的问题

$serverName = "server_name";
$connectionOptions = array(
    "Database" => "database_name",
    "Uid" => "username",
    "PWD" => "password"
);

$conn = sqlsrv_connect($serverName, $connectionOptions);
if ($conn === false) {
    die(print_r(sqlsrv_errors(), true));
}

$query = "SELECT * FROM INFORMATION_SCHEMA.TABLES";
$result = sqlsrv_query($conn, $query);
if ($result === false) {
    die(print_r(sqlsrv_errors(), true));
}

while ($row = sqlsrv_fetch_array($result, SQLSRV_FETCH_ASSOC)) {
    echo "Table Name: " . $row['TABLE_NAME'] . "<br>";
    echo "Table Type: " . $row['TABLE_TYPE'] . "<br>";
    // 其他表信息...
}