在Python中打开websocket并保持打开状态

import asyncio
import websockets

async def websocket_handler(websocket, path):
    while True:
        # 接收客户端发送的消息
        message = await websocket.recv()
        print(f"Received message: {message}")

        # 发送消息给客户端
        response = f"Server received message: {message}"
        await websocket.send(response)
        print(f"Sent response: {response}")

async def start_websocket_server():
    # 启动WebSocket服务器
    server = await websockets.serve(websocket_handler, 'localhost', 8765)

    # 保持服务器运行
    await server.wait_closed()

# 启动事件循环
asyncio.get_event_loop().run_until_complete(start_websocket_server())

pip install websockets