在PHP中迭代2个数组以显示具有相同帐户id的项目

<?php
$accounts = array(
    array('id' => 1, 'name' => 'Account 1'),
    array('id' => 2, 'name' => 'Account 2'),
    array('id' => 3, 'name' => 'Account 3')
);

$projects = array(
    array('id' => 1, 'name' => 'Project 1', 'account_id' => 1),
    array('id' => 2, 'name' => 'Project 2', 'account_id' => 2),
    array('id' => 3, 'name' => 'Project 3', 'account_id' => 2),
    array('id' => 4, 'name' => 'Project 4', 'account_id' => 3),
    array('id' => 5, 'name' => 'Project 5', 'account_id' => 3),
    array('id' => 6, 'name' => 'Project 6', 'account_id' => 4)
);

// 遍历账户数组
foreach ($accounts as $account) {
    $accountId = $account['id'];
    $accountName = $account['name'];
    
    echo "Account ID: $accountId, Account Name: $accountName<br>";

    // 遍历项目数组
    foreach ($projects as $project) {
        if ($project['account_id'] == $accountId) {
            $projectId = $project['id'];
            $projectName = $project['name'];
            
            echo "Project ID: $projectId, Project Name: $projectName<br>";
        }
    }
    
    echo "<br>";
}
?>