在PHP中显示多个表中的数据

<?php
$servername = "localhost";
$username = "username";
$password = "password";
$dbname = "database";

// 创建连接
$conn = new mysqli($servername, $username, $password, $dbname);

// 检查连接是否成功
if ($conn->connect_error) {
    die("连接失败: " . $conn->connect_error);
}
?>

<?php
$sql = "SELECT table1.column1, table2.column2
        FROM table1
        JOIN table2 ON table1.id = table2.id";

$result = $conn->query($sql);

if ($result->num_rows > 0) {
    // 输出数据
    while($row = $result->fetch_assoc()) {
        echo "表1列1: " . $row["column1"]. " - 表2列2: " . $row["column2"]. "<br>";
    }
} else {
    echo "0 结果";
}
?>