在Javascript中从两个数组中随机采样而不进行替换

function randomSampleWithoutReplacement(arr1, arr2, sampleSize) {
    // 合并两个数组
    const combinedArray = arr1.concat(arr2);
    
    // 检查样本大小是否超过数组长度
    if (sampleSize > combinedArray.length) {
        throw new Error('Sample size exceeds array length');
    }
    
    // 创建一个副本以避免修改原始数组
    const shuffledArray = combinedArray.slice();
    
    // Fisher-Yates洗牌算法
    for (let i = shuffledArray.length - 1; i > 0; i--) {
        const j = Math.floor(Math.random() * (i + 1));
        [shuffledArray[i], shuffledArray[j]] = [shuffledArray[j], shuffledArray[i]];
    }
    
    // 返回前sampleSize个元素作为样本
    return shuffledArray.slice(0, sampleSize);
}

// 示例使用
const array1 = [1, 2, 3];
const array2 = ['a', 'b', 'c'];
const sampleSize = 4;

try {
    const sample = randomSampleWithoutReplacement(array1, array2, sampleSize);
    console.log(sample);
} catch (error) {
    console.error(error.message);
}