在C++中查找连续整数的问题

#include <iostream>
#include <vector>

void findConsecutiveIntegers(const std::vector<int>& nums) {
    int start = 0;
    int length = 0;

    for (int i = 1; i < nums.size(); i++) {
        if (nums[i] - nums[i-1] == 1) {
            if (length == 0) {
                start = i - 1;
                length = 2;
            } else {
                length++;
            }
        } else {
            if (length >= 3) {
                std::cout << "连续整数序列：";
                for (int j = start; j < start + length; j++) {
                    std::cout << nums[j] << " ";
                }
                std::cout << std::endl;
            }
            start = 0;
            length = 0;
        }
    }

    if (length >= 3) {
        std::cout << "连续整数序列：";
        for (int j = start; j < start + length; j++) {
            std::cout << nums[j] << " ";
        }
        std::cout << std::endl;
    }
}

int main() {
    std::vector<int> nums = {1, 2, 3, 4, 5, 7, 8, 9, 10, 12, 13, 14};
    findConsecutiveIntegers(nums);

    return 0;
}