在有效的PHP查询()XPath中转换Javascript XPath 规范化JS XPath - > PHP

const xmlString = '<root><element>Hello, World!</element></root>';
const parser = new DOMParser();
const xmlDoc = parser.parseFromString(xmlString, 'application/xml');
const xpathResult = xmlDoc.evaluate('/root/element', xmlDoc, null, XPathResult.ANY_TYPE, null);
const element = xpathResult.iterateNext();
console.log(element.textContent); // 输出 "Hello, World!"

$xmlString = '<root><element>Hello, World!</element></root>';
$xmlDoc = new DOMDocument();
$xmlDoc->loadXML($xmlString);
$xpath = new DOMXPath($xmlDoc);
$elements = $xpath->query('/root/element');
foreach ($elements as $element) {
    echo $element->textContent; // 输出 "Hello, World!"
}

$xmlString = '<root><element>Hello, World!</element></root>';
$xmlDoc = new DOMDocument();
$xmlDoc->loadXML($xmlString);
$xpath = new DOMXPath($xmlDoc);
$elements = $xpath->query('/root/element');
foreach ($elements as $element) {
    echo $element->textContent; // 输出 "Hello, World!"
}