在将一个WebView传递给多个gtk::Button回调函数时，有没有办法避免克隆？

#include <gtk/gtk.h>

void button1_callback(GtkWidget* widget, gpointer data) {
    WebKitWebView* webView = static_cast<WebKitWebView*>(data);
    // 使用webView进行操作
}

void button2_callback(GtkWidget* widget, gpointer data) {
    WebKitWebView* webView = static_cast<WebKitWebView*>(data);
    // 使用webView进行操作
}

int main(int argc, char* argv[]) {
    gtk_init(&argc, &argv);

    GtkWidget* window = gtk_window_new(GTK_WINDOW_TOPLEVEL);
    g_signal_connect(window, "destroy", G_CALLBACK(gtk_main_quit), NULL);

    WebKitWebView* webView = WEBKIT_WEB_VIEW(webkit_web_view_new());
    // 初始化webView

    GtkWidget* button1 = gtk_button_new_with_label("Button 1");
    g_signal_connect(button1, "clicked", G_CALLBACK(button1_callback), webView);

    GtkWidget* button2 = gtk_button_new_with_label("Button 2");
    g_signal_connect(button2, "clicked", G_CALLBACK(button2_callback), webView);

    GtkWidget* vbox = gtk_vbox_new(FALSE, 5);
    gtk_box_pack_start(GTK_BOX(vbox), button1, FALSE, FALSE, 0);
    gtk_box_pack_start(GTK_BOX(vbox), button2, FALSE, FALSE, 0);

    gtk_container_add(GTK_CONTAINER(window), vbox);
    gtk_widget_show_all(window);

    gtk_main();

    return 0;
}