在列表中将一个大字典分成多个小字典

def split_dict(big_dict):
    small_dicts = {}  # 创建空的小字典

    for key, value in big_dict.items():
        first_letter = key[0]  # 获取键的首字母

        if first_letter not in small_dicts:
            small_dicts[first_letter] = {}  # 创建新的小字典

        small_dicts[first_letter][key] = value  # 将键值对添加到对应的小字典中

    return small_dicts

# 示例用法
big_dict = {
    'apple': 1,
    'banana': 2,
    'cat': 3,
    'dog': 4,
    'elephant': 5,
    'fish': 6
}

small_dicts = split_dict(big_dict)
print(small_dicts)

{
    'a': {'apple': 1},
    'b': {'banana': 2},
    'c': {'cat': 3},
    'd': {'dog': 4},
    'e': {'elephant': 5},
    'f': {'fish': 6}
}