列出urls的简陋python代码似乎不能按预期工作

import requests

def get_url_content(url):
    try:
        response = requests.get(url)
        content = response.text
        return content
    except Exception as e:
        print("Error occurred while accessing URL:", url)
        print("Error message:", str(e))
        return None

def list_urls(urls):
    for url in urls:
        content = get_url_content(url)
        if content:
            print("Content of", url, ":", content)
        else:
            print("Failed to retrieve content of", url)

# 测试代码
urls = ["https://www.example.com", "https://www.google.com", "https://www.invalidurl.com"]
list_urls(urls)