函数不返回嵌套keyof的值

type Person = {
  name: string;
  age: number;
  address: {
    street: string;
    city: string;
  };
};

function getProperty<T, K extends keyof T>(obj: T, key: K): T[K] {
  return obj[key];
}

const person: Person = {
  name: "John",
  age: 30,
  address: {
    street: "123 Main St",
    city: "New York",
  },
};

const name: string = getProperty(person, "name"); // 返回 "John"
const street: string = getProperty(person, "address.street"); // 错误，函数不返回嵌套keyof的值