从各种语言的源代码中删除/删除所有注释的通用实用程序？

import re

def remove_comments(code):
    pattern = r"#.*"
    return re.sub(pattern, "", code)

function removeComments(code) {
  return code.replace(/\/\*[\s\S]*?\*\/|\/\/.*/g, '');
}

public static String removeComments(String code) {
    return code.replaceAll("/\\*[^*]*\\*+(?:[^/*][^*]*\\*+)*/", "")
               .replaceAll("//.*");
}

#include<regex>

std::string removeComments(std::string code) {
    std::regex comments_regex(R"(\/\*[\s\S]*?\*\/|\/\/.*)");
    return std::regex_replace(code, comments_regex, "");
}

using System.Text.RegularExpressions;

public static string RemoveComments(string code) {
    return Regex.Replace(code, @"/\*[\s\S]*?\*/|//.*", "");
}