从一个矩阵的每个第i个元素中减去另一个矩阵的第n个元素

import numpy as np

def subtract_matrices(matrix1, matrix2, i, n):
    # 检查矩阵维度是否相同
    if matrix1.shape != matrix2.shape:
        raise ValueError("矩阵维度不匹配")

    # 创建一个新的矩阵，用于存储减法运算的结果
    result_matrix = np.zeros(matrix1.shape)

    # 遍历原始矩阵的每个元素
    for row in range(matrix1.shape[0]):
        for col in range(matrix1.shape[1]):
            # 将第一个矩阵的第i个元素减去第二个矩阵的第n个元素，并存储结果
            result_matrix[row, col] = matrix1[row, col] - matrix2[i, n]

    return result_matrix

# 示例用法
matrix1 = np.array([[1, 2, 3], [4, 5, 6], [7, 8, 9]])
matrix2 = np.array([[10, 20, 30], [40, 50, 60], [70, 80, 90]])
i = 1
n = 2

result = subtract_matrices(matrix1, matrix2, i, n)
print(result)