为索引范围内的每一项创建n长子列表

def create_sublists(lst, n):
    """
    将列表lst分成n个子列表
    :param lst: 原始列表
    :param n: 子列表的数量
    :return: 包含n个子列表的列表
    """
    if n <= 0:
        raise ValueError("n必须大于0")
    sublist_size = len(lst) // n
    remainder = len(lst) % n
    sublists = []
    start = 0
    for i in range(n):
        end = start + sublist_size + (1 if i < remainder else 0)
        sublists.append(lst[start:end])
        start = end
    return sublists

# 示例用法
original_list = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
n = 3
sublists = create_sublists(original_list, n)
print(sublists)