两个数组的交点(作为数据集)

function findIntersection(arr1, arr2) {
    return arr1.filter(value => arr2.includes(value));
}

const array1 = [1, 2, 3, 4];
const array2 = [3, 4, 5, 6];
console.log(findIntersection(array1, array2)); // 输出: [3, 4]

function findIntersectionByProperty(arr1, arr2, prop) {
    const set1 = new Set(arr1.map(item => item[prop]));
    return arr2.filter(item => set1.has(item[prop]));
}

const objectsArray1 = [{id: 1, name: 'Alice'}, {id: 2, name: 'Bob'}];
const objectsArray2 = [{id: 2, name: 'Bob'}, {id: 3, name: 'Charlie'}];
console.log(findIntersectionByProperty(objectsArray1, objectsArray2, 'id')); // 输出: [{id: 2, name: 'Bob'}]

function findIntersectionOptimized(arr1, arr2) {
    const set1 = new Set(arr1);
    return arr2.filter(value => set1.has(value));
}

const array1 = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10];
const array2 = [5, 6, 7, 8, 9, 10, 11, 12, 13, 14];
console.log(findIntersectionOptimized(array1, array2)); // 输出: [5, 6, 7, 8, 9, 10]

function findIntersectionByProperty(arr1, arr2, prop) {
    const set1 = new Set(arr1.map(item => item[prop]));
    return arr2.filter(item => set1.has(item[prop]));
}

const objectsArray1 = [{id: 1, name: 'Alice'}, {id: 2, name: 'Bob'}];
const objectsArray2 = [{user_id: 2, user_name: 'Bob'}, {user_id: 3, user_name: 'Charlie'}];
console.log(findIntersectionByProperty(objectsArray1, objectsArray2, 'id')); // 输出: []