前往小程序,Get更优阅读体验!
立即前往
发布
社区首页 >专栏 >typescript-exercises(六)

typescript-exercises(六)

作者头像
阿超
发布2024-11-02 11:12:33
发布2024-11-02 11:12:33
6400
代码可运行
举报
文章被收录于专栏:快乐阿超快乐阿超
运行总次数:0
代码可运行

请热爱劳动,即使不是靠它吃饭,也可以为了身体的缘故而爱它,它可以增进身心健康,免除怠惰之累。——潘恩

题目:

代码语言:javascript
代码运行次数:0
复制
/*

Intro:

    Filtering requirements have grown. We need to be
    able to filter any kind of Persons.

Exercise:

    Fix typing for the filterPersons so that it can filter users
    and return User[] when personType='user' and return Admin[]
    when personType='admin'. Also filterPersons should accept
    partial User/Admin type according to the personType.
    `criteria` argument should behave according to the
    `personType` argument value. `type` field is not allowed in
    the `criteria` field.

Higher difficulty bonus exercise:

    Implement a function `getObjectKeys()` which returns more
    convenient result for any argument given, so that you don't
    need to cast it.

    let criteriaKeys = Object.keys(criteria) as (keyof User)[];
    -->
    let criteriaKeys = getObjectKeys(criteria);

*/

interface User {
    type: 'user';
    name: string;
    age: number;
    occupation: string;
}

interface Admin {
    type: 'admin';
    name: string;
    age: number;
    role: string;
}

export type Person = User | Admin;

export const persons: Person[] = [
    { type: 'user', name: 'Max Mustermann', age: 25, occupation: 'Chimney sweep' },
    { type: 'admin', name: 'Jane Doe', age: 32, role: 'Administrator' },
    { type: 'user', name: 'Kate Müller', age: 23, occupation: 'Astronaut' },
    { type: 'admin', name: 'Bruce Willis', age: 64, role: 'World saver' },
    { type: 'user', name: 'Wilson', age: 23, occupation: 'Ball' },
    { type: 'admin', name: 'Agent Smith', age: 23, role: 'Anti-virus engineer' }
];

export function logPerson(person: Person) {
    console.log(
        ` - ${person.name}, ${person.age}, ${person.type === 'admin' ? person.role : person.occupation}`
    );
}

export function filterPersons(persons: Person[], personType: string, criteria: unknown): unknown[] {
    return persons
        .filter((person) => person.type === personType)
        .filter((person) => {
            let criteriaKeys = Object.keys(criteria) as (keyof Person)[];
            return criteriaKeys.every((fieldName) => {
                return person[fieldName] === criteria[fieldName];
            });
        });
}

export const usersOfAge23 = filterPersons(persons, 'user', { age: 23 });
export const adminsOfAge23 = filterPersons(persons, 'admin', { age: 23 });

console.log('Users of age 23:');
usersOfAge23.forEach(logPerson);

console.log();

console.log('Admins of age 23:');
adminsOfAge23.forEach(logPerson);

// In case you are stuck:
// https://www.typescriptlang.org/docs/handbook/2/functions.html#function-overloads

报错:

代码语言:javascript
代码运行次数:0
复制
index.ts(65,44): error TS2769: No overload matches this call.
  Overload 1 of 2, '(o: {}): string[]', gave the following error.
    Argument of type 'unknown' is not assignable to parameter of type '{}'.
  Overload 2 of 2, '(o: object): string[]', gave the following error.
    Argument of type 'unknown' is not assignable to parameter of type 'object'.
index.ts(67,46): error TS2571: Object is of type 'unknown'.
index.ts(76,22): error TS2345: Argument of type '(person: Person) => void' is not assignable to parameter of type '(value: unknown, index: number, array: unknown[]) => void'.
  Types of parameters 'person' and 'value' are incompatible.
    Type 'unknown' is not assignable to type 'Person'.
      Type 'unknown' is not assignable to type 'Admin'.
index.ts(81,23): error TS2345: Argument of type '(person: Person) => void' is not assignable to parameter of type '(value: unknown, index: number, array: unknown[]) => void'.
test.ts(13,5): error TS2344: Type 'false' does not satisfy the constraint 'true'.
test.ts(21,5): error TS2344: Type 'false' does not satisfy the constraint 'true'.
test.ts(29,5): error TS2344: Type 'false' does not satisfy the constraint 'true'.
test.ts(37,5): error TS2344: Type 'false' does not satisfy the constraint 'true'.

答案:

代码语言:javascript
代码运行次数:0
复制
/*

Intro:

    Filtering requirements have grown. We need to be
    able to filter any kind of Persons.

Exercise:

    Fix typing for the filterPersons so that it can filter users
    and return User[] when personType='user' and return Admin[]
    when personType='admin'. Also filterPersons should accept
    partial User/Admin type according to the personType.
    `criteria` argument should behave according to the
    `personType` argument value. `type` field is not allowed in
    the `criteria` field.

Higher difficulty bonus exercise:

    Implement a function `getObjectKeys()` which returns more
    convenient result for any argument given, so that you don't
    need to cast it.

    let criteriaKeys = Object.keys(criteria) as (keyof User)[];
    -->
    let criteriaKeys = getObjectKeys(criteria);

*/

interface User {
    type: 'user';
    name: string;
    age: number;
    occupation: string;
}

interface Admin {
    type: 'admin';
    name: string;
    age: number;
    role: string;
}

export type Person = User | Admin;

export const persons: Person[] = [
    { type: 'user', name: 'Max Mustermann', age: 25, occupation: 'Chimney sweep' },
    { type: 'admin', name: 'Jane Doe', age: 32, role: 'Administrator' },
    { type: 'user', name: 'Kate Müller', age: 23, occupation: 'Astronaut' },
    { type: 'admin', name: 'Bruce Willis', age: 64, role: 'World saver' },
    { type: 'user', name: 'Wilson', age: 23, occupation: 'Ball' },
    { type: 'admin', name: 'Agent Smith', age: 23, role: 'Anti-virus engineer' }
];

export function logPerson(person: Person) {
    console.log(
        ` - ${person.name}, ${person.age}, ${person.type === 'admin' ? person.role : person.occupation}`
    );
}

export function getObjectKeys<T>(obj:T){
    return Object.keys(obj) as (keyof T)[]
}

export function filterPersons(persons: Person[], personType: User['type'], criteria: Partial<Omit<User,'type'>>):User[];
export function filterPersons(persons: Person[], personType: Admin['type'], criteria: Partial<Omit<Admin,'type'>>):Admin[];
export function filterPersons(persons: Person[], personType: Person['type'], criteria: Partial<Person>):Person[]{
    return persons
        .filter((person) => person.type === personType)
        .filter((person) => {
            let criteriaKeys = getObjectKeys(criteria);
            return criteriaKeys.every((fieldName) => {
                return person[fieldName] === criteria[fieldName];
            });
        });
}

export const usersOfAge23 = filterPersons(persons, 'user', { age: 23 });
export const adminsOfAge23 = filterPersons(persons, 'admin', { age: 23 });

console.log('Users of age 23:');
usersOfAge23.forEach(logPerson);

console.log();

console.log('Admins of age 23:');
adminsOfAge23.forEach(logPerson);

// In case you are stuck:
// https://www.typescriptlang.org/docs/handbook/2/functions.html#function-overloads

主要是考察方法重载和范型使用

本文参与 腾讯云自媒体同步曝光计划,分享自作者个人站点/博客。
原始发表:2024-11-01,如有侵权请联系 cloudcommunity@tencent.com 删除

本文分享自 作者个人站点/博客 前往查看

如有侵权,请联系 cloudcommunity@tencent.com 删除。

本文参与 腾讯云自媒体同步曝光计划  ,欢迎热爱写作的你一起参与!

评论
登录后参与评论
0 条评论
热度
最新
推荐阅读
领券
问题归档专栏文章快讯文章归档关键词归档开发者手册归档开发者手册 Section 归档