std::filesystem::path::append

path& operator/=(const path& p);	(1)	(since C++17)
template< class Source > path& operator/=( const Source& source );	(2)	(since C++17)
template< class Source > path& append( const Source& source );	(3)	(since C++17)
template< class InputIt > path& append( InputIt first, InputIt last );	(4)	(since C++17)

1%29首先，将首选目录分隔符追加到this，除非下列任何条件都是真实的：

%2A分离器将是多余的%28*this已经以分隔符%29结尾

%2A*this为空，或者添加它会以其他方式将相对路径转换为绝对路径。

%2Ap是一条空路。

%2Ap.native()从目录分隔符开始。

然后，追加p.native()维护的路径名。*this

如果p.has_root_name()是true...

2，3%29与%281%29相同，但接受任何std::basic_string，，，std::basic_string_view或指向空终止多字符序列的输入迭代器.。相当于return operator/=(path(source));...

4%29与%281%29相同，但接受指定多字符字符串的任何迭代器对。相当于return operator/=(path(first, last));

参数

p	-	pathname to append
source	-	std::basic_string, std::basic_string_view, null-terminated multicharacter string, or an input iterator pointing to a null-terminated multicharacter sequence, which represents a path name (either in portable or in native format)
first, last	-	pair of InputIterators that specify a multicharacter sequence that represents a path name

类型要求

-输入必须符合输入器的要求。

-InputIt的值类型必须是编码字符类型%28 char，wchar[医]T，char16[医]T和char32[医]t%29

返回值

*this...

例外

可抛filesystem_error关于基础OS API错误或std::bad_alloc如果内存分配失败。

例

二次

#include <iostream>
#include <filesystem>
namespace fs = std::filesystem;
int main() {
    fs::path p1 = "C:";
    p1 /= "Users"; // does not insert a separator
    std::cout << "\"C:\" / \"Users\" == " << p1 << '\n';
    p1 /= "batman"; // inserts fs::path::preferred_separator, '\' on Windows
    std::cout << "\"C:\" / \"Users\" / \"batman\" == " << p1 << '\n';
}

二次

可能的产出：

二次

"C:" / "Users" == "C:Users"
"C:" / "Users" / "batman" == "C:Users\batman"

二次

另见

concatoperator+=	concatenates two paths without introducing a directory separator (public member function)
operator/	concatenates two paths with a directory separator (function)

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最后更新于：2017-12-18