sys_connect_by_path函数是为了配合递归查询的函数，递归查询可以参考我之前的博客：https://blog.csdn.net/u014427391/article/details/84996259...， sys_connect_by_path函数是将递归查到的数据加上特定的符号，看起来更明显 connect by递归查询配合sys_connect_by_path基本语法是： select sys_connect_by_path...然后给个例子，scott用户登录 select sys_connect_by_path(ename, '>') from emp start with ename = 'KING' connect...可能遇到的报错，ORA-30004:使用SYS_CONNECT_BY_PATH函数时，不能将分隔符作为列值的一部分 原因是当使用SYS_CONNECT_BY_PATH 函数时,不能将分隔符作为字段值的一部分...假如这样的sql，ename里面有@这个字符，就会报错，方法是修改sql换个字符，或者改数据 select sys_connect_by_path(ename, '@') from emp start
sys_connect_by_path函数是为了配合递归查询的函数，递归查询可以参考我之前的博客：https://blog.csdn.net/u014427391/article/details/84996259...， sys_connect_by_path函数是将递归查到的数据加上特定的符号，看起来更明显 connect by递归查询配合sys_connect_by_path基本语法是： select sys_connect_by_path...然后给个例子，scott用户登录 select sys_connect_by_path(ename, '>') from emp start with ename = 'KING' connect...by prior empno = mgr; 可能遇到的报错，ORA-30004:使用SYS_CONNECT_BY_PATH函数时，不能将分隔符作为列值的一部分 原因是当使用SYS_CONNECT_BY_PATH...函数时,不能将分隔符作为字段值的一部分 假如这样的sql，ename里面有@这个字符，就会报错，方法是修改sql换个字符，或者改数据 select sys_connect_by_path(ename,
利用层次查询中的伪列level和表达式sys_connect_by_path，查询如下： select level, ename, job, sys_connect_by_path(ename,'->'...) from emp start with mgr is null connect by prior empno = mgr / 查询结果如下： SQL> col sys_connect_by_path...(ename,'->') for a35 SQL> / LEVEL ENAME JOB SYS_CONNECT_BY_PATH(ENAME,'->') ---------- ---...prior ..语句轻松的将这个层次关系查询出来，当然也可以根据需求进一步排序： SQL> ed Wrote file afiedt.buf 1 select level, ename, job, sys_connect_by_path...也可以指定关心的员工及其下属关系： SQL> ed Wrote file afiedt.buf 1 select level, ename, job, sys_connect_by_path(ename
MEUM_TEST.create_time is '创建时间'; comment on column MEUM_TEST.org_level is '组织级别'; 插入表数据 输出层级关系（从上往下） select sys_connect_by_path...where t.org_level=4 start with parent_id=0 connect by prior t.cid=t.parent_id; 查找单个节点的根(从下往上) select sys_connect_by_path
DISTINCT c1, get_c2 (c1) cc2 FROM table1; 也可以利用分析函数和 CONNECT_BY 实现： SELECT c1, SUBSTR (MAX (SYS_CONNECT_BY_PATH...PARTITION BY code ORDER BY LENGTH (name1) DESC) rn2 FROM ( SELECT code, SYS_CONNECT_BY_PATH...SELECT * FROM v1; 更简单的写法如下： [sql] view plain copy -- name1如果有顺序，则按照其seq排序 SELECT code, LTRIM (MAX (SYS_CONNECT_BY_PATH...1 AND code = PRIOR code GROUP BY code; -- name1如果没有顺序，则按照rowid排序 SELECT code, LTRIM (MAX (SYS_CONNECT_BY_PATH
FROM PL_PLAN_BASE A left JOIN (SELECT B.CATEGORY_ID, REGEXP_SUBSTR(SYS_CONNECT_BY_PATH...( B.CLASS_NAME,'/'),'[^/]+',1,1,'i') FIRST_NAME, REGEXP_SUBSTR(SYS_CONNECT_BY_PATH(...FROM PL_PLAN_BASE A left JOIN (SELECT B.CATEGORY_ID, REGEXP_SUBSTR(SYS_CONNECT_BY_PATH...( B.CLASS_NAME,'/'),'[^/]+',1,1,'i') FIRST_NAME, REGEXP_SUBSTR(SYS_CONNECT_BY_PATH(...( B.CLASS_NAME,'/'),'[^/]+',1,1,'i') FIRST_NAME, REGEXP_SUBSTR(SYS_CONNECT_BY_PATH(
SQL> select id,ltrim(max(sys_connect_by_path(mc,',')),',') row2col from (select id,mc, id+(row_number...------------------ 1 11111,22222 2 11111,22222 3 11111,22222,33333 SQL> select id,replace(max(sys_connect_by_path
from dual 6 replace替换函数 将Scott中的c替换为Boy select replace('Scott','c','Boy') from dual; //得到SBoyott 7 sys_connect_by_path...递归函数 Oracle函数:sys_connect_by_path 主要用于树查询(层次查询) 以及 多列转行 语法为：select ... sys_connect_by_path(column_name...,'connect_symbol') from table start with ... connect by ... prior 案例 select sys_connect_by_path(t.mpd_name
SELECT substr(sys_connect_by_path(dutywork, ';'), 2) FROM (select dutywork,rownum rn
a.event, a.status, connect_by_isleaf as isleaf, sys_connect_by_path...a.event, a.status, connect_by_isleaf as isleaf, sys_connect_by_path...a.event, 5 a.status, 6 connect_by_isleaf as isleaf, 7 sys_connect_by_path...a.event, 5 a.status, 6 connect_by_isleaf as isleaf, 7 sys_connect_by_path
PARTITION BY tranid ORDER BY tranobject) tranobjects FROM purchase) GROUP BY tranid; --也可以用sys_connect_by_path...(PARTITION BY tranid ORDER BY levels desc ) AS tranobjects --保留最大的那个 from (select tranid,sys_connect_by_path...tranid and tranobject ) ); --对所有购买单元项进行排列组合，即数据挖掘的X^Y项 create view all_zuhe as select substr(sys_connect_by_path
linesize 300 col intersect_sql format a1000 spool intersect_result.sql SELECT 'select '|| SUBSTR (MAX (SYS_CONNECT_BY_PATH...column_name, ',')), 2)||' from '||table_name||chr(10)|| ' intersect '||chr(10)|| 'select '|| SUBSTR (MAX (SYS_CONNECT_BY_PATH
3、扩展：构造递归路径 Oracle中提供了SYS_CONNECT_BY_PATH函数用来进行连接路径。....*, SUBSTR(SYS_CONNECT_BY_PATH(FTID,'->'),3) NAME_PATH FROM T_BF_INSTANCEENTRY TBIE START WITH (FTID...T_SAL_ORDERENTRY') CONNECT BY FSID= PRIOR FTID AND FSTABLENAME =PRIOR FTTABLENAME 基于上个查询，增加了一列SUBSTR(SYS_CONNECT_BY_PATH...SELECT TBIE.*, SUBSTR(SYS_CONNECT_BY_PATH(FTID,'->'),3)NAME_PATH, (connect_by_root FTID) ROOT FROM T_BF_INSTANCEENTRY...select * from table1 ) select * from tempTableName 拿我们的案例举例就是： with flow_temp as ( SELECT TBIE.*, SUBSTR(SYS_CONNECT_BY_PATH
a.event, a.status, connect_by_isleaf as isleaf, sys_connect_by_path...a.event, a.status, connect_by_isleaf as isleaf, sys_connect_by_path...5 a.status, 6 connect_by_isleaf as isleaf, 7 sys_connect_by_path...5 a.status, 6 connect_by_isleaf as isleaf, 7 sys_connect_by_path
_3_name FROM ( SELECT org_pk, org_name, SYS_CONNECT_BY_PATH...(org_pk, '/') || '/' c_pk_path, SYS_CONNECT_BY_PATH (org_name, '/') || '/
hrmresource where id in (waigaunyanshourens); 行，报“无效数字”的错误； 第二种思路：由于第一种思路老是不知道什么原因，也就另寻他路； select ltrim(max(sys_connect_by_path...dbms_output.put_line(ltrim(waiguanstr,’,’)); 输出结果： 人名A 人名B 人名C 人名A,人名B,人名C 第二种解决方法： select ltrim(max(sys_connect_by_path
n from all_objects where rownum <= 5))) b ) select replace(sys_connect_by_path...from (select rownum - 1 n from all_objects where rownum <= 20 * 5)) ) select replace(sys_connect_by_path...) ) ) SELECT REPLACE(MAX(str),',') STR FROM (SELECT y,SYS_CONNECT_BY_PATH
fls.id flid, fls.class_name name, SUBSTR (SYS_CONNECT_BY_PATH...2) || '.' || xx, '.') xuhao FROM ( SELECT flid, name, SYS_CONNECT_BY_PATH
6、层次化查询还支持一个特殊的函数 SYS_CONNECT_BY_PATH ， SYS_CONNECT_BY_PATH （ exp ， char ），这个函数返回从根节点到这一行计算其中每个exp 表达式的值
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