quarter_是否可以在DateTimePicker中使用Quarter_将DATETIME(Date Time)转换为Quarter(int) SSIS - 腾讯云开发者社区 - 腾讯云

开发者社区

文档建议反馈控制台

最新优惠活动

文章/答案/技术大牛

发布

SQL函数 QUARTER

SQL函数 QUARTER日期函数，它将一年中的季度作为日期表达式的整数返回。...也可以使用 QUARTER() 方法调用从 ObjectScript 调用此函数：$SYSTEM.SQL.Functions.QUARTER(date-expression)示例以下示例均返回数字 1，...因为日期（2 月 22 日）位于该年的第一季度：SELECT {fn QUARTER('2018-02-22')} AS ODBCDateQ1SELECT {fn QUARTER(64701)} AS...HorologDateQ1以下示例均返回当前季度：SELECT {fn QUARTER({fn NOW()})} AS Q_Now, {fn QUARTER(CURRENT_DATE)} AS...Q_CurrD, {fn QUARTER(CURRENT_TIMESTAMP)} AS Q_CurrTstamp, {fn QUARTER($ZTIMESTAMP)} AS Q_ZTstamp

7752 0

python设计模式-状态模式

"You can't insert another quarter") elif self.state == self.STATE_NO_QUARTER: # 如果没有投过...self.state = self.STATE_HAS_QUARTER print("You inserted a quarter") elif self.state...(self): # 退回25分 if self.state == self.STATE_HAS_QUARTER: print("Quarter returned..." def insert_quarter(self): # 投币并且改变状态 print("You inserted a quarter")..." def insert_quarter(self): print("You can't insert another quarter") def eject_quarter

3511 0

您找到你想要的搜索结果了吗？

是的

没有找到

状态（State）模式

You insert a quarter Quarter returned You turned, but there's no quarter You need to pay first You insert...a quarter You turned......You insert a quarter You turned... A gumball comes rolling out the slot......You haven't insert a quarter You insert a quarter You can't insert another quarter You turned......You insert a quarter You turned... A gumball comes rolling out the slot...

3083 0

python合并两列

需要把数字类型转化为字符串类型，再进行连接第一种 df1 = pd.DataFrame({'Year': ['2014', '2015'], 'quarter': ['q1', 'q2']})...df1['period'] = df[['Year', 'quarter']].apply(lambda x: ''.join(x), axis=1) df1 Year quarter period...0 2014 q1 2014q1 1 2015 q2 2015q2 第二种 df2 = pd.DataFrame({'Year': ['2014', '2015'], 'quarter...': ['q1', 'q2']}) df2["period"] = df["Year"].map(str) + df["quarter"] df2 Year quarter period...': ['q1', 'q2']}) df3['period'] = df["Year"].str.cat(df["quarter"],sep='|') df Year quarter period

3.8K2 0

地表最强Power Query 日期表

Number", each Date.QuarterOfYear([Date])), InsertQuarterName = Table.AddColumn(InsertQuarterNumber, "Quarter...Name", each "Q" & Number.ToText([Quarter Number])), InsertMonth = Table.AddColumn(InsertQuarterName,...", "Year and Month", "Year and Week", "Quarter Name", "Quarter Number", "Quarter and Year", "Start of...Quarter", "End of Quarter", "Month Name", "Month Name Short", "Month Number", "Month and Year", "Month...", Int64.Type}, {"Year and Month", Int64.Type}, {"Year and Week", Int64.Type}, {"Quarter Number", Int64

8793 0

kettle生成节假日数据原来还可以这样操作？

.、12 月份 year string 2000 年份 quarter_name string Q1 季度名称 quarter_number string 1 季度 year_quarter string...= "Q1"; quarter_number = "1"; year_quarter = year + "-" + quarter_name...= "Q2"; quarter_number = "2"; year_quarter = year + "-" + quarter_name...= "Q3"; quarter_number = "3"; year_quarter = year + "-" + quarter_name...= "Q4"; quarter_number = "4"; year_quarter = year + "-" + quarter_name

8803 0

人脸关键点检测

']['x'], res['left_eye_lower_left_quarter']['y']], [res['left_eye_lower_right_quarter...']['x'], res['left_eye_upper_left_quarter']['y']], [res['left_eye_upper_right_quarter...']['x'], res['right_eye_lower_left_quarter']['y']], [res['right_eye_lower_right_quarter...']['x'], res['right_eye_upper_left_quarter']['y']], [res['right_eye_upper_right_quarter...']['y']], [res['left_eye_upper_right_quarter']['x'], res['left_eye_upper_right_quarter

2.5K2 0

设计模式之状态模式（一）

System.out.println("You can't insert another quarter"); } else if (state == NO_QUARTER) {...state = HAS_QUARTER; System.out.println("You inserted a quarter"); } else if (state == SOLD_OUT...) { state = HAS_QUARTER; System.out.println("You inserted a quarter");...) { System.out.println("Quarter returned"); state = NO_QUARTER; } else...if (state == NO_QUARTER) { System.out.println("You haven't inserted a quarter");

3094 0

Amazon Alexa超级碗广告，及Amazon 2019年第四季度财务报告

Fourth Quarter 2019 Net sales increased 21% to $87.4 billion in the fourth quarter, compared with $72.4...billion in fourth quarter 2018...., net sales increased 21% compared with fourth quarter 2018....billion in fourth quarter 2018....net income of $3.0 billion, or $6.04 per diluted share, in fourth quarter 2018.

3501 0

python获取指定日期范围内的每一天，每个月，每季度

(tempvalue[0] + "Q1") elif tempvalue[1] in ['04','05','06']: quarter_list.append(...tempvalue[0] + "Q2") elif tempvalue[1] in ['07', '08', '09']: quarter_list.append...(tempvalue[0] + "Q3") elif tempvalue[1] in ['10', '11', '12']: quarter_list.append...(tempvalue[0] + "Q4") quarter_set = set(quarter_list) quarter_list = list(quarter_set) quarter_list.sort...() return quarter_list

1.7K1 0

MySQL的日期时间计算速查表

(create_time) = QUARTER(NOW()) AND YEAR (create_time) = YEAR (NOW()) 查询上个季度新增数据 select * from test...where QUARTER(create_time) = QUARTER(DATE_SUB(now(),interval 1 QUARTER)) 查询本月新增数据 select * from test...()),1) + interval QUARTER(CURDATE())*3-1 month); 前一quarter的第一天 select concat(date_format(LAST_DAY(...前一quarter的最后一天 select LAST_DAY(MAKEDATE(EXTRACT(YEAR FROM CURDATE()),1) + interval QUARTER(CURDATE())...()：函数返回给定日期值（1到4之间的数字）的一年中的季度，语法：QUARTER(date) date，必须项。

1.9K2 0

基于Hadoop生态圈的数据仓库实践 —— 进阶技术（六）

date customer_zip_code shipping_zip_code product_category month_name customer_city shipping_city quarter...这个查询按产品（product_category列）和日期维度的三个层次级别（year、quarter和month列）分组返回销售金额。..., month CLUSTER BY product_category , year , quarter , month; 查询结果如下图所示。...: ', quarter) else concat('month: ', month) end time, order_amount,...gid, date FROM ( SELECT product_category, year, quarter, month, min(date) date, SUM(order_amount

3741 0

数据拆分、合并思路(Java)

; BeanUtils.copyProperties(satisfactionInfoOfYearRes, satisfactionInfoDO); Map quarter...("1",firstQuarter); quarter.put("2",secondQuarter); quarter.put("3",thirdQuarter); quarter.put("4"...,fourthQuarter); quarter.forEach((k,v)->{ if (v == null){ return; } satisfactionInfoDO.setQuarter...`quarter`,a.YEAR,a.satisfaction,a.create_time,a.create_by , -- 合并季度数据 GROUP_CONCAT(a....= quarters[i]; BigDecimal satisfaction = new BigDecimal(satisfactions[i]); switch (quarter){ case

3676 0

使用Tidyr重塑数据

long_DF % gather(Quarter, Revenue, Qtr.1:Qtr.4) head(long_DF, 24) # note, for brevity, I only...Quarter列代表观察值的某个季度（Q1或者Q2,3,4），而Revenue代表原数据的值。...#上述相同结果的四种不同写法 DF %>% gather(Quarter, Revenue, Qtr.1:Qtr.4) DF %>% gather(Quarter, Revenue, -Group, -...Year) DF %>% gather(Quarter, Revenue, 3:6) DF %>% gather(Quarter, Revenue, Qtr.1, Qtr.2, Qtr.3, Qtr.4..., c("Time_Interval", "Interval_ID")) long_DF %>% separate(Quarter, c("Time_Interval", "Interval_ID"),

8671 0

sparksql-unpivot子句介绍

4200, 3100, null, null); -- 列名被用作反透视列 SELECT * FROM sales_quarterly UNPIVOT ( sales FOR quarter...IN (q1, q2, q3, q4) ); +------+---------+-------+ | year | quarter | sales | +------+---------+-...IN (q1 AS Q1, q2 AS Q2, q3 AS Q3, q4 AS Q4) ) AS up; +------+---------+-------+ | year | quarter...------+-------+ -- 多列值反透视 SELECT * FROM sales_quarterly UNPIVOT EXCLUDE NULLS ( (first_quarter..., second_quarter) FOR half_of_the_year IN ( (q1, q2) AS H1, (q3, q4)

1061 0

python datetime时间格式的相互转换问题

= now.month / 3 if now.month % 3 == 0 else now.month / 3 + 1 print('now_quarter:',now_quarter) # 本周第一天和最后一天...- timedelta(days=1) print('this_quarter_start:',this_quarter_start) print('this_quarter_end:',this_quarter_end...) # 上季第一天和最后一天 last_quarter_end = this_quarter_start - timedelta(days=1) last_quarter_start = datetime.datetime...(last_quarter_end.year, last_quarter_end.month - 2, 1) print('last_quarter_end:',last_quarter_end) print...('last_quarter_start:',last_quarter_start) # 本年第一天和最后一天 this_year_start = datetime.datetime(now.year,

4K2 0

Mysql 日期查询

) , '%Y%m' ) , date_format( 时间字段名, '%Y%m' ) ) =1查询本季度数据select * from `ht_invoice_information` where QUARTER...(create_date)=QUARTER(now());查询上季度数据select * from `ht_invoice_information` where QUARTER(create_date)...=QUARTER(DATE_SUB(now(),interval 1 QUARTER));查询本年数据select * from `ht_invoice_information` where YEAR(...(order_time) = QUARTER(NOW())6、查询上季度数据SELECT * FROM `order` WHERE QUARTER(order_time) = QUARTER(DATE_SUB...(NOW(),INTERVAL 1 QUARTER))7、查询5分钟内的数据select * from tb_log where createtime >= DATE_SUB(NOW(),INTERVAL

5.6K3 0

M-Arch（6）第五个示例：DAC

_1 1 #define CIRCLE_QUARTER_2 2 #define CIRCLE_QUARTER_3 3 #define CIRCLE_QUARTER...= 1 + (angle / 90u); switch (circle_quarter) { case CIRCLE_QUARTER_1: // 00 .. 89...sin_value = sinus_I_quarter[angle]; break; case CIRCLE_QUARTER_2: // 90 .. 179...sin_value = sinus_I_quarter[180 - angle]; break; case CIRCLE_QUARTER_3: // 180 ..... 269 sin_value = -sinus_I_quarter[angle - 180]; break; case CIRCLE_QUARTER

4792 0

M-Arch（番外9）GD32L233评测-DAC波形发生器（三角波，方波，正弦波，任意波）

_1 1 #define CIRCLE_QUARTER_2 2 #define CIRCLE_QUARTER_3 3 #define CIRCLE_QUARTER...= 1 + (angle / 90u); switch (circle_quarter) { case CIRCLE_QUARTER_1: // 00 .. 89...sin_value = sinus_I_quarter[angle]; break; case CIRCLE_QUARTER_2: // 90 .. 179...sin_value = sinus_I_quarter[180 - angle]; break; case CIRCLE_QUARTER_3: // 180 ..... 269 sin_value = -sinus_I_quarter[angle - 180]; break; case CIRCLE_QUARTER

6193 0

【R语言进行数据挖掘】回归分析

> year <- rep(2008:2010, each=4) > quarter <- rep(1:4, 3) > cpi <- c(162.2, 164.6, 166.5, 166.0, + 166.2...,sep="Q"), at=1:12, las=3) 接下来，观察CPI与其他变量例如‘year(年份)’和‘quarter(季度)’之间的相关关系。...> cor(year,cpi) > cor(quarter,cpi) 输出如下： > cor(quarter,cpi) [1] 0.3738028 > cor(year,cpi) [1] 0.9096316...> cor(quarter,cpi) [1] 0.3738028 由上图可知，CPI与年度之间的关系是正相关，并且非常紧密，相关系数接近1；而它与季度之间的相关系数大约为0.37，只是有着微弱的正相关...# 建立模型fit > fit <- lm(cpi ~ year + quarter) > fit 输出结果如下： Call: lm(formula = cpi ~ year + quarter) Coefficients

1.1K3 0

点击加载更多

扫码

添加站长进交流群

领取专属 10元无门槛券

手把手带您无忧上云

扫码加入开发者社群

相关资讯

热门标签

活动推荐

运营活动

活动名称

广告关闭