Linux系统下采集摄像头数据通常涉及以下几个基础概念:
以下是一个简单的使用V4L2接口采集摄像头数据的C语言示例代码:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <fcntl.h>
#include <errno.h>
#include <sys/ioctl.h>
#include <sys/mman.h>
#include <linux/videodev2.h>
#define CLEAR(x) memset(&(x), 0, sizeof(x))
int main(int argc, char *argv[]) {
int fd;
struct v4l2_format fmt;
struct v4l2_requestbuffers req;
struct v4l2_buffer buf;
char *buffer;
int ret;
fd = open("/dev/video0", O_RDWR);
if (fd < 0) {
perror("Failed to open device");
return -1;
}
CLEAR(fmt);
fmt.type = V4L2_BUF_TYPE_VIDEO_CAPTURE;
fmt.fmt.pix.width = 640;
fmt.fmt.pix.height = 480;
fmt.fmt.pix.pixelformat = V4L2_PIX_FMT_YUYV;
fmt.fmt.pix.field = V4L2_FIELD_INTERLACED;
ret = ioctl(fd, VIDIOC_S_FMT, &fmt);
if (ret < 0) {
perror("Failed to set format");
close(fd);
return -1;
}
CLEAR(req);
req.count = 4;
req.type = V4L2_BUF_TYPE_VIDEO_CAPTURE;
req.memory = V4L2_MEMORY_MMAP;
ret = ioctl(fd, VIDIOC_REQBUFS, &req);
if (ret < 0) {
perror("Failed to request buffers");
close(fd);
return -1;
}
buffer = malloc(req.count * fmt.fmt.pix.sizeimage);
if (!buffer) {
perror("Failed to allocate memory");
close(fd);
return -1;
}
// MMAP and other operations would go here...
free(buffer);
close(fd);
return 0;
}
/dev/video0
)存在,并且应用程序有足够的权限访问它。/dev/video0
)存在,并且应用程序有足够的权限访问它。通过以上步骤,通常可以解决Linux下摄像头数据采集的基本问题。如果遇到更复杂的问题,可能需要进一步调试或查阅相关文档。