js如何带参数跳转页面跳转页面

// 假设要跳转到example.html，并传递两个参数param1和param2
let param1 = "value1";
let param2 = "value2";

// 构建带参数的URL
let url = `example.html?param1=${encodeURIComponent(param1)}&param2=${encodeURIComponent(param2)}`;

// 跳转到新页面
window.location.href = url;

// 存储数据
localStorage.setItem('param1', 'value1');
localStorage.setItem('param2', 'value2');

// 跳转到新页面
window.location.href = 'example.html';

// 读取数据
let param1 = localStorage.getItem('param1');
let param2 = localStorage.getItem('param2');

let param1 = "value1";
let param2 = "value2";

// 打开新窗口并发送消息
let newWindow = window.open('example.html');
newWindow.postMessage({param1, param2}, 'http://目标页面的域名');

window.addEventListener('message', function(event) {
  if (event.origin !== 'http://发送页面的域名') return; // 安全检查
  let {param1, param2} = event.data;
  console.log(param1, param2);
});