android如何判断url中的域名

import java.net.MalformedURLException;
import java.net.URL;

public class URLUtils {
    public static String getDomainFromURL(String urlString) {
        try {
            URL url = new URL(urlString);
            return url.getHost();
        } catch (MalformedURLException e) {
            e.printStackTrace();
            return null;
        }
    }

    public static void main(String[] args) {
        String urlString = "https://www.example.com/path/to/resource";
        String domain = getDomainFromURL(urlString);
        if (domain != null) {
            System.out.println("Domain: " + domain);
        } else {
            System.out.println("Invalid URL");
        }
    }
}