Php如何在模式弹出菜单中打开引导程序选择框选项，而不是常规的组合框

<button onclick="openModal()">打开菜单</button>

<div id="myModal" class="modal">
  <div class="modal-content">
    <select id="programSelect">
      <option value="program1">引导程序1</option>
      <option value="program2">引导程序2</option>
      <option value="program3">引导程序3</option>
    </select>
    <button onclick="selectProgram()">选择</button>
  </div>
</div>

.modal {
  display: none;
  position: fixed;
  z-index: 1;
  left: 0;
  top: 0;
  width: 100%;
  height: 100%;
  overflow: auto;
  background-color: rgba(0, 0, 0, 0.4);
}

.modal-content {
  background-color: #fefefe;
  margin: 15% auto;
  padding: 20px;
  border: 1px solid #888;
  width: 300px;
}

function openModal() {
  var modal = document.getElementById("myModal");
  modal.style.display = "block";
}

function selectProgram() {
  var programSelect = document.getElementById("programSelect");
  var selectedProgram = programSelect.value;
  // 在这里可以根据选择的引导程序执行相应的操作
  console.log("选择的引导程序：" + selectedProgram);
  
  var modal = document.getElementById("myModal");
  modal.style.display = "none";
}