Javascript:如何找出两个数字数组的差异

function findDifference(arr1, arr2) {
  // 找出arr1中不在arr2中的元素
  const diff1 = arr1.filter(num => !arr2.includes(num));
  
  // 找出arr2中不在arr1中的元素
  const diff2 = arr2.filter(num => !arr1.includes(num));
  
  // 返回两个数组的差异
  return diff1.concat(diff2);
}

const array1 = [1, 2, 3, 4, 5];
const array2 = [3, 4, 5, 6, 7];
const difference = findDifference(array1, array2);
console.log(difference); // 输出 [1, 2, 6, 7]

function findDifference(arr1, arr2) {
  // 将arr2中的元素转为Set对象
  const set2 = new Set(arr2);
  
  // 找出arr1中不在arr2中的元素
  const diff1 = arr1.reduce((result, num) => {
    if (!set2.has(num)) {
      result.push(num);
    }
    return result;
  }, []);
  
  // 找出arr2中不在arr1中的元素
  const diff2 = arr2.reduce((result, num) => {
    if (!arr1.includes(num)) {
      result.push(num);
    }
    return result;
  }, []);
  
  // 返回两个数组的差异
  return diff1.concat(diff2);
}

const array1 = [1, 2, 3, 4, 5];
const array2 = [3, 4, 5, 6, 7];
const difference = findDifference(array1, array2);
console.log(difference); // 输出 [1, 2, 6, 7]