C++如何在一个函数的一行中读取更多的整数？

#include <iostream>
#include <vector>

void readIntegers(std::vector<int>& numbers, int count) {
    for (int i = 0; i < count; ++i) {
        std::cin >> numbers[i];
    }
}

int main() {
    const int numberOfIntegers = 5;
    std::vector<int> integers(numberOfIntegers);
    readIntegers(integers, numberOfIntegers);
    // 输出读取的整数以验证
    for (const auto& num : integers) {
        std::cout << num << " ";
    }
    return 0;
}

#include <iostream>
#include <vector>
#include <iterator>

void readIntegers(std::vector<int>& numbers) {
    std::copy_n(std::istream_iterator<int>(std::cin), numbers.size(), numbers.begin());
}

int main() {
    const int numberOfIntegers = 5;
    std::vector<int> integers(numberOfIntegers);
    readIntegers(integers);
    // 输出读取的整数以验证
    for (const auto& num : integers) {
        std::cout << num << " ";
    }
    return 0;
}

#include <iostream>
#include <sstream>
#include <vector>

void readIntegers(std::vector<int>& numbers) {
    std::string line;
    std::getline(std::cin, line);
    std::stringstream ss(line);
    int num;
    while (ss >> num) {
        numbers.push_back(num);
    }
}

int main() {
    const int numberOfIntegers = 5;
    std::vector<int> integers;
    readIntegers(integers);
    // 输出读取的整数以验证
    for (const auto& num : integers) {
        std::cout << num << " ";
    }
    return 0;
}