计算字符串中相同的字母，但不是全部长度

def find_duplicate_chars(string):
    char_count = {}
    duplicates = []

    # 计算每个字符的出现次数
    for char in string:
        if char in char_count:
            char_count[char] += 1
        else:
            char_count[char] = 1

    # 找出出现多次的字符
    for char, count in char_count.items():
        if count > 1:
            duplicates.append((char, count))

    return duplicates

# 测试示例
string = "hello world"
result = find_duplicate_chars(string)
print(result)