筛选包含日期字符串的列表

import re

def filter_date_strings(lst):
    date_strings = []
    pattern = r"\d{4}-\d{2}-\d{2}"  # 日期字符串的正则表达式模式

    for item in lst:
        if re.search(pattern, item):
            date_strings.append(item)

    return date_strings

# 示例用法
my_list = ["2022-01-01", "2022-01-02", "2022-01-03", "abc", "123"]
filtered_list = filter_date_strings(my_list)
print(filtered_list)

import java.util.ArrayList;
import java.util.List;
import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class DateStringFilter {
    public static List<String> filterDateStrings(List<String> list) {
        List<String> dateStrings = new ArrayList<>();
        String pattern = "\\d{4}-\\d{2}-\\d{2}";  // 日期字符串的正则表达式模式

        for (String item : list) {
            Pattern regex = Pattern.compile(pattern);
            Matcher matcher = regex.matcher(item);

            if (matcher.find()) {
                dateStrings.add(item);
            }
        }

        return dateStrings;
    }

    // 示例用法
    public static void main(String[] args) {
        List<String> myList = List.of("2022-01-01", "2022-01-02", "2022-01-03", "abc", "123");
        List<String> filteredList = filterDateStrings(myList);
        System.out.println(filteredList);
    }
}