模拟用于测试表单的filedata的正确方法是什么？

// 创建一个用于存储表单数据的对象
const formData = {
  name: 'John Doe',
  email: 'johndoe@example.com',
  age: 30,
  gender: 'male'
};

// 使用JavaScript的`append`方法添加表单数据到`formData`对象中
formData.append('address', '123 Main St, Anytown USA');
formData.append('phone', '123-456-7890');

// 使用`submit`方法将`formData`对象提交到服务器端进行处理
document.getElementById('my-form').addEventListener('submit', function(event) {
  event.preventDefault();
  const form = document.getElementById('my-form');
  form.disabled = true;
  fetch('/submit-form', {
    method: 'POST',
    body: formData
  }).then(response => {
    // 处理服务器端返回的结果
  }).catch(error => {
    // 处理请求失败的错误
  });
});

<?php
if ($_SERVER['REQUEST_METHOD'] == 'POST') {
  $name = $_POST['name'];
  $email = $_POST['email'];
  $age = $_POST['age'];
  $gender = $_POST['gender'];
  $address = $_POST['address'];
  $phone = $_POST['phone'];

  // 将获取到的表单数据存储到数据库中
  $db = new PDO('sqlite:example.db');
  $stmt = $db->prepare('INSERT INTO users (name, email, age, gender, address, phone) VALUES (?, ?, ?, ?, ?, ?, ?)');
  $stmt->execute([$name, $email, $age, $gender, $address, $phone]);
}
?>