根据长度从字符串中删除最后一位数字

def remove_last_digit(s):
    if s and s[-1].isdigit():
        return s[:-1]
    return s

# 示例
input_string = "12345"
result = remove_last_digit(input_string)
print(result)  # 输出: "1234"

function removeLastDigit(str) {
    if (str && !isNaN(str[str.length - 1])) {
        return str.slice(0, -1);
    }
    return str;
}

// 示例
const inputString = "12345";
const result = removeLastDigit(inputString);
console.log(result); // 输出: "1234"

public class Main {
    public static String removeLastDigit(String s) {
        if (s != null && Character.isDigit(s.charAt(s.length() - 1))) {
            return s.substring(0, s.length() - 1);
        }
        return s;
    }

    public static void main(String[] args) {
        String inputString = "12345";
        String result = removeLastDigit(inputString);
        System.out.println(result);  // 输出: "1234"
    }
}

using System;

public class Program
{
    public static string RemoveLastDigit(string s)
    {
        if (!string.IsNullOrEmpty(s) && char.IsDigit(s[s.Length - 1]))
        {
            return s.Substring(0, s.Length - 1);
        }
        return s;
    }

    public static void Main()
    {
        string inputString = "12345";
        string result = RemoveLastDigit(inputString);
        Console.WriteLine(result);  // 输出: "1234"
    }
}

def remove_last_digit(s):
    if s:
        return s[:-1]
    return s