查找嵌套列表的最小最大值，并使用索引返回其他嵌套列表中的相应值

def find_min_max(nested_list):
    min_val = float('inf')
    max_val = float('-inf')

    def helper(nested_list):
        nonlocal min_val, max_val
        for i, val in enumerate(nested_list):
            if isinstance(val, list):
                helper(val)
            else:
                min_val = min(min_val, val)
                max_val = max(max_val, val)

    helper(nested_list)

    return min_val, max_val


def find_values_by_index(nested_list, index):
    result = []

    def helper(nested_list, index):
        nonlocal result
        for val in nested_list:
            if isinstance(val, list):
                helper(val, index)
            elif val == index:
                result.append(val)

    helper(nested_list, index)

    return result


# 示例嵌套列表
nested_list = [1, [2, [3, 4], 5], [6, [7, 8], 9]]

# 查找最小值和最大值
min_val, max_val = find_min_max(nested_list)
print("最小值:", min_val)
print("最大值:", max_val)

# 使用索引返回其他嵌套列表中的相应值
index = 4
values = find_values_by_index(nested_list, index)
print("索引为{}的值: {}".format(index, values))