Java中数组的地址问题(hashCode解析):
import java.util.Arrays;
public class Action1 {
public static void main(...初始数组
int [] array0= {5,9,9,9,65,65,95,9,5,6,69,6,65,899};
System.out.println("0->生成地址:\t"+array0.hashCode...());
//2、赋值数组
int [] array1=array0;
System.out.println("1->未生成新地址:\t"+array1.hashCode());
//3...());
//4、new创建数组,相当于array2的Arrays.copyOf
int[] array3 = new int[array0.length];
for (int i = 0;...i < array0.length; i++) {
array3[i]=array0[i];
}
System.out.println("3->生成新地址:\t"+array3.hashCode