有没有办法使用itertools groupby删除列表中相邻的重复项，但保留原始索引？

from itertools import groupby

def remove_duplicates_with_index(lst):
    result = []
    for key, group in groupby(enumerate(lst), lambda x: x[1]):
        indices = [index for index, _ in group]
        result.append(lst[indices[0]])
    return result

# 示例用法
lst = [1, 1, 2, 3, 3, 3, 4, 5, 5]
result = remove_duplicates_with_index(lst)
print(result)  # 输出: [1, 2, 3, 4, 5]