当两个矩形不相交时，我的Javafx程序的转换不会继续播放

import javafx.animation.Animation;
import javafx.animation.KeyFrame;
import javafx.animation.Timeline;
import javafx.application.Application;
import javafx.geometry.Bounds;
import javafx.scene.Scene;
import javafx.scene.layout.Pane;
import javafx.scene.paint.Color;
import javafx.scene.shape.Rectangle;
import javafx.stage.Stage;
import javafx.util.Duration;

public class CollisionDetectionExample extends Application {

    private Rectangle rect1;
    private Rectangle rect2;
    private Timeline timeline;

    @Override
    public void start(Stage primaryStage) {
        Pane root = new Pane();
        Scene scene = new Scene(root, 400, 400);
        primaryStage.setScene(scene);
        primaryStage.show();

        rect1 = new Rectangle(50, 50, 100, 100);
        rect1.setFill(Color.RED);

        rect2 = new Rectangle(200, 200, 100, 100);
        rect2.setFill(Color.BLUE);

        root.getChildren().addAll(rect1, rect2);

        timeline = new Timeline(new KeyFrame(Duration.seconds(0.5), event -> {
            // 检测碰撞
            Bounds bounds1 = rect1.getBoundsInParent();
            Bounds bounds2 = rect2.getBoundsInParent();
            if (!bounds1.intersects(bounds2)) {
                // 两个矩形不相交，停止转换的播放
                timeline.stop();
            }
        }));
        timeline.setCycleCount(Animation.INDEFINITE);
        timeline.play();
    }

    public static void main(String[] args) {
        launch(args);
    }
}