将文件Json (array)放入zip文件[Java]

import java.io.*;
import java.util.zip.ZipEntry;
import java.util.zip.ZipOutputStream;

public class ZipJsonFile {
    public static void main(String[] args) {
        String jsonFilePath = "path/to/your/json/file.json"; // JSON文件路径
        String zipFilePath = "path/to/your/output/file.zip"; // 输出的ZIP文件路径

        try {
            // 读取JSON文件内容
            String jsonContent = readFile(jsonFilePath);

            // 创建ZIP文件并添加JSON内容
            createZipFile(zipFilePath, jsonContent);

            System.out.println("ZIP文件创建成功！");
        } catch (IOException e) {
            e.printStackTrace();
        }
    }

    private static String readFile(String filePath) throws IOException {
        StringBuilder content = new StringBuilder();
        try (BufferedReader reader = new BufferedReader(new FileReader(filePath))) {
            String line;
            while ((line = reader.readLine()) != null) {
                content.append(line);
            }
        }
        return content.toString();
    }

    private static void createZipFile(String zipFilePath, String content) throws IOException {
        try (FileOutputStream fos = new FileOutputStream(zipFilePath);
             ZipOutputStream zos = new ZipOutputStream(fos)) {
            // 创建ZIP条目
            ZipEntry zipEntry = new ZipEntry("data.json");
            zos.putNextEntry(zipEntry);

            // 写入JSON内容
            zos.write(content.getBytes());
            zos.closeEntry();
        }
    }
}