将儒略日期转换为公历日期-C编程

#include <stdio.h>

// 判断是否为闰年
int isLeapYear(int year) {
    if ((year % 4 == 0 && year % 100 != 0) || year % 400 == 0) {
        return 1;
    }
    return 0;
}

// 计算每个月的天数
int getDaysInMonth(int year, int month) {
    int daysInMonth[] = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
    if (month == 2 && isLeapYear(year)) {
        return 29;
    }
    return daysInMonth[month - 1];
}

// 将儒略日期转换为公历日期
void convertJulianToDate(int julianDate) {
    int year, month, day;
    int remainingDays = julianDate;

    // 计算年份
    year = (remainingDays - 1) / 365;
    remainingDays -= year * 365;

    // 计算月份和天数
    for (month = 1; month <= 12; month++) {
        int daysInMonth = getDaysInMonth(year, month);
        if (remainingDays <= daysInMonth) {
            day = remainingDays;
            break;
        }
        remainingDays -= daysInMonth;
    }

    // 输出公历日期
    printf("公历日期为：%d年%d月%d日\n", year, month, day);
}

int main() {
    int julianDate;

    printf("请输入儒略日期：");
    scanf("%d", &julianDate);

    convertJulianToDate(julianDate);

    return 0;
}