可以利用enumerate()：
count=0
for index,line in enumerate(open(filepath,'r')):
count+=1
五. python中的zip...x = [1, 2, 3]
y = [4, 5, 6]
z = [7, 8, 9]
xyz = zip(x, y, z)
print(list(xyz))
#结果：
[(1, 4, 7), (2, 5..., 8), (3, 6, 9)]
Process finished with exit code 0
x = ["id", "name", "age"]
y = [3306,"dh",18]
xy =...定义一个 __iter__() 方法来返回一个带有 __next__() 方法的对象。...如果类已定义了 __next__()，则 __iter__() 可以简单地返回 self:
class Reverse:
"""Iterator for looping over a sequence
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