如何组合运算符RXJS？

import { of } from 'rxjs';
import { map, filter } from 'rxjs/operators';

const source$ = of(1, 2, 3, 4, 5);

source$.pipe(
  map(x => x * 2),
  filter(x => x > 5)
).subscribe(console.log);

import { of } from 'rxjs';
import { map, filter } from 'rxjs/operators';

const source$ = of(1, 2, 3, 4, 5);

source$
  .pipe(map(x => x * 2))
  .pipe(filter(x => x > 5))
  .subscribe(console.log);

import { of, merge, concat } from 'rxjs';

const source1$ = of(1, 2, 3);
const source2$ = of(4, 5, 6);

const merged$ = merge(source1$, source2$);
const concatenated$ = concat(source1$, source2$);

merged$.subscribe(console.log); // 输出：1, 2, 3, 4, 5, 6
concatenated$.subscribe(console.log); // 输出：1, 2, 3, 4, 5, 6

import { of, combineLatest, zip } from 'rxjs';

const source1$ = of(1, 2, 3);
const source2$ = of('a', 'b', 'c');

const combined$ = combineLatest(source1$, source2$);
const zipped$ = zip(source1$, source2$);

combined$.subscribe(console.log); // 输出：[3, 'a'], [3, 'b'], [3, 'c']
zipped$.subscribe(console.log); // 输出：[1, 'a'], [2, 'b'], [3, 'c']