如何根据第n个元素的最近值对元组列表进行分组？

def group_tuples_by_nearest_value(tuples, n, target):
    diff_list = []
    for tup in tuples:
        diff = abs(tup[n-1] - target)
        diff_list.append(diff)

    min_diff = min(diff_list)
    result_dict = {}
    for i, diff in enumerate(diff_list):
        if diff == min_diff:
            if min_diff in result_dict:
                result_dict[min_diff].append(tuples[i])
            else:
                result_dict[min_diff] = [tuples[i]]

    return list(result_dict.values())

# 示例用法
tuples = [(1, 5, 10), (2, 6, 11), (3, 7, 12), (4, 8, 13), (5, 9, 14)]
n = 2
target = 7
result = group_tuples_by_nearest_value(tuples, n, target)
print(result)

[[(2, 6, 11), (3, 7, 12)]]