如何按文件夹对文件(字符串)列表进行分组，并对分组进行select方法

def group_files_by_folder(file_list):
    groups = {}  # 用字典存储分组结果，键为文件夹路径，值为文件列表
    for file_path in file_list:
        folder_path = get_folder_path(file_path)  # 获取文件所在文件夹路径
        if folder_path in groups:
            groups[folder_path].append(file_path)  # 将文件添加到对应的分组中
        else:
            groups[folder_path] = [file_path]  # 创建新的分组并添加文件

    return groups

def select_group(groups, select_method):
    selected = select_method(groups)  # 根据具体需求选择不同的select方法
    return selected

# 示例的select方法：按文件夹名称进行排序
def select_by_folder_name(groups):
    sorted_groups = sorted(groups.items(), key=lambda x: x[0])  # 按文件夹名称进行排序
    return sorted_groups

# 示例的select方法：筛选特定文件夹的文件
def select_by_specific_folder(groups, folder_name):
    if folder_name in groups:
        return groups[folder_name]
    else:
        return []

# 示例的select方法：获取所有文件夹的文件数目
def select_file_count_by_folder(groups):
    result = {}
    for folder, files in groups.items():
        result[folder] = len(files)
    return result

# 示例用法
file_list = ['file1', 'file2', 'file3', 'folder1/file4', 'folder1/file5', 'folder2/file6']
groups = group_files_by_folder(file_list)
selected_group = select_group(groups, select_by_folder_name)
print(selected_group)