如何找出在express中为方法/url对注册了哪些处理程序？

const express = require('express');
const app = express();

// 定义路由处理程序
const handler1 = (req, res, next) => {
  // 处理程序1的逻辑
  next();
};

const handler2 = (req, res, next) => {
  // 处理程序2的逻辑
  next();
};

// 注册路由处理程序
app.get('/example', handler1, handler2);

// 查找注册的处理程序
const method = 'GET';
const url = '/example';

const matchedHandlers = app._router.stack.filter(layer => {
  if (layer.route && layer.route.path === url && layer.route.methods[method.toLowerCase()]) {
    return true;
  }
  return false;
});

// 输出匹配的处理程序
matchedHandlers.forEach(handler => {
  console.log(handler.route.path);
  console.log(handler.route.methods);
});