如何忽略xml命名空间？

import xml.etree.ElementTree as ET

xml_string = '''<root xmlns="http://www.example.com/ns">
   <element1>Text1</element1>
   <element2>Text2</element2>
</root>
'''

root = ET.fromstring(xml_string)

for elem in root.iter():
    print(elem.tag.split('}')[1])

import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.xpath.XPath;
import javax.xml.xpath.XPathConstants;
import javax.xml.xpath.XPathFactory;
import org.w3c.dom.Document;
import org.w3c.dom.NodeList;

public class IgnoreXMLNamespace {
    public static void main(String[] args) throws Exception {
        String xmlString = "<root xmlns=\"http://www.example.com/ns\<element1>Text1</element1<element2>Text2</element2></root>";

        DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
        dbf.setNamespaceAware(false);
        DocumentBuilder dBuilder = dbf.newDocumentBuilder();
        Document doc = dBuilder.parse(new ByteArrayInputStream(xmlString.getBytes(StandardCharsets.UTF_8)));

        XPathFactory xPathFactory = XPathFactory.newInstance();
        XPath xPath = xPathFactory.newXPath();
        NodeList nodeList = (NodeList) xPath.evaluate("//*[local-name()='element1']", doc, XPathConstants.NODESET);

        for (int i = 0; i< nodeList.getLength(); i++) {
            System.out.println(nodeList.item(i).getTextContent());
        }
    }
}

using System.Xml.Linq;
using System.Xml.XPath;

class IgnoreXMLNamespace {
    static void Main() {
        string xmlString = "<root xmlns=\"http://www.example.com/ns\<element1>Text1</element1<element2>Text2</element2></root>";

        XDocument doc = XDocument.Parse(xmlString);

        var element1 = doc.XPathSelectElement("//*[local-name()='element1']");
        Console.WriteLine(element1.Value);
    }
}