如何忽略JAXB中的意外元素情况？

import javax.xml.bind.annotation.XmlAccessType;
import javax.xml.bind.annotation.XmlAccessorType;
import javax.xml.bind.annotation.XmlAnyElement;
import javax.xml.bind.annotation.XmlRootElement;

@XmlRootElement
@XmlAccessorType(XmlAccessType.FIELD)
public class MyObject {
    @XmlAnyElement
    private Object any;

    public Object getAny() {
        return any;
    }

    public void setAny(Object any) {
        this.any = any;
    }
}

import javax.xml.bind.JAXBContext;
import javax.xml.bind.JAXBException;
import javax.xml.bind.Unmarshaller;
import java.io.StringReader;

public class Main {
    public static void main(String[] args) {
        String xml = "<myObject><unexpectedElement>Some data</unexpectedElement></myObject>";

        try {
            JAXBContext jaxbContext = JAXBContext.newInstance(MyObject.class);
            Unmarshaller unmarshaller = jaxbContext.createUnmarshaller();
            MyObject myObject = (MyObject) unmarshaller.unmarshal(new StringReader(xml));
            System.out.println("Parsed object: " + myObject.getAny());
        } catch (JAXBException e) {
            e.printStackTrace();
        }
    }
}