如何将difftime的值从小时转换为天？

double difftime(time_t time1, time_t time0);

double days = difftime / (60 * 60 * 24);

#include <stdio.h>
#include <time.h>

int main() {
    time_t time1, time0;
    double difftime;

    // 假设time1和time0是两个时间点的值
    time1 = time(NULL);
    time0 = time(NULL) - 3600;  // 假设时间差为1小时

    difftime = time1 - time0;

    double days = difftime / (60 * 60 * 24);
    printf("差值的天数为：%lf\n", days);

    return 0;
}