如何将简单类序列化/反序列化为XML并返回

public class Person
{
    public string Name { get; set; }
    public int Age { get; set; }
    public string Gender { get; set; }
}

public static string SerializeToXml<T>(T obj)
{
    using var stringWriter = new StringWriter();
    var serializer = new XmlSerializer(typeof(T));
    serializer.Serialize(stringWriter, obj);
    return stringWriter.ToString();
}

public static T DeserializeFromXml<T>(string xmlString)
{
    using var stringReader = new StringReader(xmlString);
    var serializer = new XmlSerializer(typeof(T));
    return (T)serializer.Deserialize(stringReader);
}

public static void Main(string[] args)
{
    var person = new Person { Name = "John Doe", Age = 30, Gender = "Male" };

    // 序列化为XML
    var xmlString = SerializeToXml(person);
    Console.WriteLine("Serialized XML:");
    Console.WriteLine(xmlString);

    // 反序列化为对象
    var deserializedPerson = DeserializeFromXml<Person>(xmlString);
    Console.WriteLine("\nDeserialized object:");
    Console.WriteLine($"Name: {deserializedPerson.Name}, Age: {deserializedPerson.Age}, Gender: {deserializedPerson.Gender}");
}