如何将时间增量的结果转换为仅小时数

import re

def convert_time_increment(time_increment):
    # 解析时间增量
    pattern = r'(\d+)天\s?(\d+)小时\s?(\d+)分钟'
    match = re.match(pattern, time_increment)
    if match:
        days = int(match.group(1))
        hours = int(match.group(2))
        minutes = int(match.group(3))
        # 将天数转换为小时数
        hours += days * 24
        # 将分钟数转换为小时数
        hours += minutes / 60
        return hours

    # 解析时间差
    pattern = r'(\d+):(\d+):(\d+)'
    match = re.match(pattern, time_increment)
    if match:
        hours = int(match.group(1))
        return hours

    return None

# 示例用法
time_increment = "2天 5小时 30分钟"
hours = convert_time_increment(time_increment)
print(hours)  # 输出：53.5