如何将嵌套的JSON数据结构扁平化为具有键值对的对象

def flatten_json(json_data, prefix=''):
    flattened_data = {}
    
    for key, value in json_data.items():
        new_key = prefix + '.' + key if prefix else key
        
        if isinstance(value, dict):
            flattened_data.update(flatten_json(value, new_key))
        else:
            flattened_data[new_key] = value
    
    return flattened_data

import json

nested_json = {
  "name": "John",
  "age": 30,
  "address": {
    "street": "123 Main Street",
    "city": "New York",
    "state": "NY"
  },
  "phone_numbers": [
    {
      "type": "home",
      "number": "555-1234"
    },
    {
      "type": "work",
      "number": "555-5678"
    }
  ]
}

flattened_data = flatten_json(nested_json)
print(json.dumps(flattened_data, indent=2))

{
  "name": "John",
  "age": 30,
  "address.street": "123 Main Street",
  "address.city": "New York",
  "address.state": "NY",
  "phone_numbers.0.type": "home",
  "phone_numbers.0.number": "555-1234",
  "phone_numbers.1.type": "work",
  "phone_numbers.1.number": "555-5678"
}