如何将二进制数的字符串转换为C中的字符(每个字符必须有一个半字节)？

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

void binaryStringToChar(const char* binaryString, char* result) {
    int len = strlen(binaryString);
    int groupCount = len / 4;
    int remainder = len % 4;
    int i, j;

    // 补齐字符串长度为4的倍数
    char* paddedString = (char*)malloc((len + (4 - remainder) % 4 + 1) * sizeof(char));
    strcpy(paddedString, binaryString);
    for (i = 0; i < 4 - remainder; i++) {
        strcat(paddedString, "0");
    }

    // 将每组二进制数转换为字符
    for (i = 0; i < groupCount; i++) {
        char group[5];
        strncpy(group, paddedString + i * 4, 4);
        group[4] = '\0';
        int decimal = strtol(group, NULL, 2);
        result[i] = (char)decimal;
    }
    result[groupCount] = '\0';

    free(paddedString);
}

int main() {
    const char* binaryString = "011000010110001001100011";
    char result[9];
    binaryStringToChar(binaryString, result);
    printf("Result: %s\n", result);

    return 0;
}