如何将二进制串的文字串表示转换为二进制串？

def text_to_binary(text):
    binary_string = ""
    for char in text:
        ascii_value = ord(char)  # 将字符转换为ASCII码
        binary_string += bin(ascii_value)[2:].zfill(8)  # 将ASCII码转换为二进制串，并补齐到8位
    return binary_string

def binary_to_text(binary):
    text = ""
    for i in range(0, len(binary), 8):
        binary_byte = binary[i:i+8]  # 每8位为一个字节
        decimal_value = int(binary_byte, 2)  # 将二进制串转换为十进制
        text += chr(decimal_value)  # 将十进制转换为字符
    return text

# 示例用法
binary_string = text_to_binary("Hello, world!")
print(binary_string)  # 输出：0100100001100101011011000110110001101111001000000111011101101111011100100110110001100100

text = binary_to_text(binary_string)
print(text)  # 输出：Hello, world!