如何在dataframe的列(numpy对象)中找到满足条件的索引？

import pandas as pd
import numpy as np

# 创建一个示例DataFrame
data = {'A': [1, 2, 3, 4, 5],
        'B': [10, 20, 30, 40, 50]}
df = pd.DataFrame(data)

# 找到满足条件的索引
condition = df['A'] > 2
indexes = np.where(condition)[0]

print(indexes)

import pandas as pd

# 创建一个示例DataFrame
data = {'A': [1, 2, 3, 4, 5],
        'B': [10, 20, 30, 40, 50]}
df = pd.DataFrame(data)

# 找到满足条件的索引
indexes = df.query('A > 2').index

print(indexes)

import pandas as pd

# 创建一个示例DataFrame
data = {'A': [1, 2, 3, 4, 5],
        'B': [10, 20, 30, 40, 50]}
df = pd.DataFrame(data)

# 找到满足条件的索引
indexes = df.loc[df['A'] > 2].index

print(indexes)