如何在crawler4j中将参数传递给shouldVisit()方法？

import edu.uci.ics.crawler4j.crawler.Page;
import edu.uci.ics.crawler4j.parser.HtmlParseData;
import edu.uci.ics.crawler4j.url.WebURL;
import edu.uci.ics.crawler4j.crawler.CrawlController;
import java.util.List;

public class MyCrawler extends WebCrawler {

    private String parameter;

    public MyCrawler(String parameter) {
        this.parameter = parameter;
    }

    @Override
    public boolean shouldVisit(Page referringPage, WebURL url) {
        // 在这里可以使用传递的参数
        System.out.println("传递的参数为：" + parameter);

        // 根据需求编写shouldVisit()的逻辑判断
        return true;
    }

    @Override
    public void visit(Page page) {
        // 实现visit()方法的逻辑
        if (page.getParseData() instanceof HtmlParseData) {
            HtmlParseData htmlParseData = (HtmlParseData) page.getParseData();
            String text = htmlParseData.getText();
            String html = htmlParseData.getHtml();
            List<WebURL> links = htmlParseData.getOutgoingUrls();

            // 处理页面数据
        }
    }

    public static void main(String[] args) throws Exception {
        String parameter = "参数值";

        // 创建CrawlController对象，并传递参数
        CrawlController crawlController = new CrawlController();
        crawlController.addSeed("https://www.example.com");
        crawlController.setPolitenessDelay(1000);
        crawlController.startNonBlocking(MyCrawler.class, 1);

        // 启动爬虫
        crawlController.waitUntilFinish();
    }
}